Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Exercises - Page 463: 8

Answer

$8a. \sqrt 3$ $8b. -\sqrt 3$

Work Step by Step

$8a. tan (\frac{\pi}{3})$ tangent of $\frac{\pi}{3}$ is $\sqrt 3$ $8b. tan (\frac{-\pi}{3})$ This angle is in the fourth quadrant, in which tangent is negative. $-\sqrt 3$
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