Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises: 87

Answer

$\approx -0.579352$

Work Step by Step

RECALL: The change-of-base formula for logarithms: $\log_b{x} = \dfrac{\log_a{x}}{\log_a{b}}$ Use the formula above and use base 10 to obtain: $\log_9{0.28} = \dfrac{\log{0.28}}{\log{9}}$ Use a scientific calculator and round-off the answer to six decimal places to obtain: $\approx -0.579352$
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