Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Review - Exercises: 26

Answer

$\log_{49} (\frac{1}{7}) = -\frac{1}{2}$

Work Step by Step

$Write$ $the$ $equation$ $in$ $logarithmic$ $form:$ $49^{-\frac{1}{2}} = \frac{1}{7}$ Exponential form to logarithmic form: $b^c = a \rightarrow \log_b a = c$ Plug in 49 for b, $-\frac{1}{2}$ for c, and $\frac{1}{7}$ for a $$49^{-\frac{1}{2}} = \frac{1}{7} \rightarrow \log_{49} (\frac{1}{7}) = -\frac{1}{2}$$
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