## Precalculus: Mathematics for Calculus, 7th Edition

$x=5$
$3^{2x-7}=27$ Rewrite $27$ as $3^{3}$: $3^{2x-7}=3^{3}$ If $3^{2x-7}=3^{3}$, then $2x-7=3$ $2x-7=3$ Solve for $x$: $2x=3+7$ $2x=10$ $x=\dfrac{10}{2}$ $x=5$