## Precalculus: Mathematics for Calculus, 7th Edition

$Evaluate$ $the$ $expression$ $without$ $using$ $a$ $calculator:$ $e^{2\ln7}$ Make 2 the exponent of 7 $$e^{\ln 7^{2}}$$ $$e^{\ln 49}$$ Use the property of natural logarithms: $e^{\ln x} = x$ $$e^{\ln 49} = 49$$