Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 2

Answer

$\color{blue}{3}$

Work Step by Step

RECALL: (1) $a^{m/n} = \sqrt[n]{a^m}=(\sqrt[n]{a})^m$ Use the rule above t obtain: $27^{2/3} = \sqrt[3]{27}$ With $27=3^3$, the expression above is equivalent to: $=\sqrt[3]{3^3}$ Use rule (2) above to obtain: $=\color{blue}{3}$
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