Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 19

Answer

$2$

Work Step by Step

RECALL: $\sqrt[n]{a} = a^{1/n}$ Use the rule above by to obtain: $\sqrt[5]{32} = 32^{1/5}$ Since $32=2^5$, then the expression above simplifies to: $=\color{blue}{2}$
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