Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 21

Answer

$\color{blue}{2}$

Work Step by Step

RECALL: $\sqrt[n]{a} = a^{1/n}$ Use the rule above by to obtain: $-\sqrt[5]{-32} = -(-32)^{1/5}$ Since $-32=(-2)^5$, then the expression above simplifies to: $=-(-2) \\=\color{blue}{2}$
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