Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises: 10

Answer

$\color{blue}{1}$

Work Step by Step

RECALL: (1) $(a+b)(a-b) = a^2-b^2$ (2) For $a\gt0$, $(\sqrt{a})^2 = a$ Use rule (1) above by to obtain: $=2^2 - (\sqrt{3})^2 \\=4-(\sqrt3)^2$ Use rule (2) above to obtain: $\\=4-3 \\=\color{blue}{1}$
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