Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 74: 12

Answer

$6$

Work Step by Step

RECALL: $\sqrt[n]{a} = a^{1/n}$ Use the rule above by to obtain: $\sqrt[3]{216} = 216^{1/3}$ Since $216=6^3$, then $\color{blue}{216^{1/3} = 6}$
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