Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises - Page 667: 69

Answer

$\dfrac {\tan ^{2}t-1}{sec^{2}t}=\dfrac {\tan ^{2}t-1}{\tan ^{2}t+1}=\dfrac {\cot t\left( \tan ^{2}t-1\right) }{\cot t\left( \tan ^{2}t+1\right) }=\dfrac {\tan t-\cot t}{\tan t+\cot t}$

Work Step by Step

$\dfrac {\tan ^{2}t-1}{sec^{2}t}=\dfrac {\tan ^{2}t-1}{\tan ^{2}t+1}=\dfrac {\cot t\left( \tan ^{2}t-1\right) }{\cot t\left( \tan ^{2}t+1\right) }=\dfrac {\tan t-\cot t}{\tan t+\cot t}$
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