Answer
$\dfrac {1}{1-\sin \theta }+\dfrac {1}{1+\sin \theta }=2sec^{2}\theta $
Work Step by Step
$\dfrac {1}{1-\sin \theta }+\dfrac {1}{1+\sin \theta }=\dfrac {\left( 1+\sin \theta \right) +\left( 1-\sin \theta \right) }{\left( 1-\sin \theta \right) \left( 1+\sin \theta \right) }=\dfrac {2}{1-\sin ^{2}\theta }=\dfrac {2}{\cos ^{2}\theta }=2sec^{2}\theta $
