Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.2 Verifying Trigonometric Identities - 7.2 Exercises: 63

Answer

$\dfrac {\cot \alpha +1}{\cot \alpha -1}=\dfrac {1+\tan \alpha }{1-\tan \alpha }$

Work Step by Step

$\dfrac {\cot \alpha +1}{\cot \alpha -1}=\dfrac {\dfrac {\cos \alpha }{\sin \alpha }+1}{\dfrac {\cos \alpha }{\sin \alpha }-1}=\dfrac {\cos \alpha +\sin \alpha }{\cos \alpha -\sin \alpha }=\dfrac {\dfrac {\cos \alpha +\sin \alpha }{\cos \alpha }}{\dfrac {\cos \alpha -\sin \alpha }{\cos a}}=\dfrac {1+\tan \alpha }{1-\tan \alpha }$
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