Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.5 Equations of Lines and Linear Models - 2.5 Exercises - Page 247: 83

Answer

$-2x_1x_2(m_1m_2+1)=0$

Work Step by Step

From the previous result: $-2m_1m_2x_1x_2-2x_1x_2=0$, we have $-2x_1x_2(m_1m_2+1)=0$
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