Answer
$\sqrt {(x_2-x_1)^2+(m_2x_2-m_1x_1)^2}$
Work Step by Step
Given $P(x_1,m_1x_1)$ and $Q(x_2,m_2x_2)$, we have $d(P,Q)=\sqrt {(x_2-x_1)^2+(m_2x_2-m_1x_1)^2}$
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