Answer
No.
Work Step by Step
Step 1. Given $A(-1,-3), B(-5,12), C(1,-11)$, for $AB$, we have $m_1=\frac{-3-12}{-1-(-5)}=-\frac{15}{4}$
Step 2. For $BC$, we have $m_2=\frac{12-(-11)}{-5-1}=-\frac{23}{6}$
Step 3. For $AC$, we have $m_3=\frac{-3-(-11)}{-1-1}=-\frac{9}{2}$
Step 4. Since we do not have $m_1=m_2=m_3$, the three points are not collinear.
