Answer
No.
Work Step by Step
Step 1. Given $A(0,9), B(-3,-7), C(2,19)$, for $AB$, we have $m_1=\frac{-7-9}{-3-0}=\frac{16}{3}$
Step 2. For $BC$, we have $m_2=\frac{-7-19}{-3-2}=\frac{26}{5}$
Step 3. For $AC$, we have $m_3=\frac{9-19}{0-2}=5$
Step 4. Since we do not have $m_1=m_2=m_3$, the three points are not collinear.