Answer
$\sqrt {x_1^2+m_1^2x_1^2}$
Work Step by Step
Given $O(0,0)$ and $P(x_1,m_1x_1)$, we have $d(O,P)=\sqrt {(x_1-0)^2+(m_1x_1-0)^2}=\sqrt {x_1^2+m_1^2x_1^2}$
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