## Precalculus (6th Edition)

$\color{blue}{\left\{-1, 5\right\}}$
RECALL: $|x|=a \longrightarrow x=a \text{ or } x = -a$ Use the rule above to have: $|2-x|= 3 \longrightarrow 2-x=3 \text{ or } 2-x = -3$ Solve each equation to obtain: $2-x=3 \\-x=3-2 \\-x=1 \\x=-1$ or $2-x=-3 \\-x=-3-2 \\-x=-5 \\x=5$ Thus, the solution set is $\color{blue}{\left\{-1, 5\right\}}$.