Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 181: 110

Answer

$-\frac{13}{29},-\frac{15}{13}$.

Work Step by Step

Step 1. Rewrite the equation as $|\frac{8x-1}{3x+2}|=7$, we can remove the absolute sign and separate the cases to: $\frac{8x-1}{3x+2}=7$ and $\frac{8x-1}{3x+2}=-7$ Step 2. For $\frac{8x-1}{3x+2}=7$, we have $8x-1=21x+14\longrightarrow 13x=-15$, thus $x=-\frac{15}{13}$ Step 3. For $\frac{8x-1}{3x+2}=-7$, we have $8x-1=-21x-14\longrightarrow 29x=-13$, thus $x=-\frac{13}{29}$ Step 4. Check the answers and they fit, thus the solutions are $x=-\frac{13}{29}$ and $x=-\frac{15}{13}$.
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