Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 181: 114

Answer

$(-\infty,\frac{6}{5}]\cup[2,\infty)$

Work Step by Step

Step 1. We can remove the absolute sign to get: $8-5x\geq2$ or $8-5x\leq-2$ Step 2. For $8-5x\geq2$, we have $5x\leq6$, thus $x\leq\frac{6}{5}$ Step 3. For $8-5x\leq-2$, we have $5x\geq10$, thus $x\geq2$ Step 4. The solution set is $(-\infty,\frac{6}{5}]\cup[2,\infty)$
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