Answer
$(-\infty,\frac{6}{5}]\cup[2,\infty)$
Work Step by Step
Step 1. We can remove the absolute sign to get: $8-5x\geq2$ or $8-5x\leq-2$
Step 2. For $8-5x\geq2$, we have $5x\leq6$, thus $x\leq\frac{6}{5}$
Step 3. For $8-5x\leq-2$, we have $5x\geq10$, thus $x\geq2$
Step 4. The solution set is $(-\infty,\frac{6}{5}]\cup[2,\infty)$