Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 181: 117

Answer

$(-\frac{17}{3},1)$

Work Step by Step

Step 1. Rewrite the inequality as $|3x+7|\lt10$ Step 2. We can remove the absolute sign to get: $-10\lt 3x+7\lt10\longrightarrow -17\lt 3x\lt3 \longrightarrow -\frac{17}{3}\lt x\lt1$ or in interval notation $(-\frac{17}{3},1)$
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