Answer
$(-\infty,-\frac{1}{7}]\cup(1,\infty)$
Work Step by Step
Step 1. We can remove the absolute sign to get: $7x-3\gt4$ or $7x-3\lt-4$
Step 2. For $7x-3\gt4$, we have $7x\gt7$, thus $x\gt1$
Step 3. For $7x-3\lt-4$, we have$7x\lt-1$, thus $x\lt-\frac{1}{7}$
Step 4. The solution set is $(-\infty,-\frac{1}{7}]\cup(1,\infty)$
