Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 91

Answer

$ 2x(x+6-2a)(x+6+2a)$

Work Step by Step

$ 2x^{3}-8a^{2}x+24x^{2}+72x=\quad$... we have a common factor, $2x$ $=2x(x^{2}-4a^{2}+12x+36)$ the terms not containing $a$ form a recognizable trinomial $=2x[(x^{2}+12x+36)-4a^{2}]$ $=2x[(x^{2}+2\cdot 6x+6^{2})-4a^{2}]$ ... a square of a sum, $A^{2}+2AB+B^{2}=(A+B)^{2}$ $=2x[(x+6)^{2}-4a^{2}]$ ... the brackets contain a difference of squares, $(x+6)^{2}-(2a)^{2}$ $=2x(x+6-2a)(x+6+2a)$
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