Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 96

Answer

$\displaystyle \frac{6(x+2)}{x^{3/4}}$

Work Step by Step

$[x^{1/4}=x^{1-3/4}=x\cdot x^{-3/4}]$ $ 12x^{-3/4}+6x^{1/4}=6\cdot 2x^{-3/4}+6x\cdot x^{-3/4}\qquad$... factor out $6x^{-3/4}$ $=6x^{-3/4}(2+x)\qquad $... $a^{-n}=\displaystyle \frac{1}{a^{n}}$ = $\displaystyle \frac{6(x+2)}{x^{3/4}}$
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