Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set: 63

Answer

$(4x+3)(16x^2-12x+9)$

Work Step by Step

RECALL: A sum of two cubes can be factored using the formula: $a^3+b^3 = (a+b)(a^2-ab+b^2)$ The given expression can be written as: $=4^3x^3+3^3 \\(4x)^3+3^3$ The binomial above is a sum of two cubes. Factor using the formula above with $a=4x$ and $b=3$ to obtain: $=(4x+3)[(4x)^2-4x(3) + 3^2) \\=(4x+3)(16x^2-12x+9)$
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