Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 97

Answer

$ -(x+3)^{1/2}(x+2)$

Work Step by Step

$\left[(x+3)^{3/2}=(x+3)^{1+\frac{1}{2}}=(x+3)(x+3)^{1/2}\right]$ $(x+3)^{1/2}-(x+3)^{3/2}=(x+3)^{1/2}-(x+3)(x+3)^{1/2}\qquad$ ... factor out $(x+3)^{1/2}$ $=(x+3)^{1/2}[1-(x+3)]$ $=(x+3)^{1/2}(-x-2)\qquad$... factor out -1 $=-(x+3)^{1/2}(x+2)$
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