Answer
$ (x^{2}+6)(6x^{2}-1)$
Work Step by Step
Temporarily substitute $t=x^{2}$.
The expression is now
$6t^{2}+35t-6$
For the trinomial, we search for factors of ac whose sum is b
and we find $+36(-1)=-6\cdot 6,\quad 36-1=+35$
rewrite bx and factor in pairs
$=6t^{2}+36t-t-6$
$=6t(t+6)-(t+6)$
$=(t+6)(6t-1)$
bring back x
$=(x^{2}+6)(6x^{2}-1)$
