Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set: 65

Answer

$\frac{a^8}{b^8}$

Work Step by Step

Use the product rule and the definition of negative exponents. $(a^{-2}b^3)(a^{10}b^{-11})=a^{-2+10}b^{3+(-11)}=a^8b^{-8}=\frac{a^8}{b^8}$
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