Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set: 41

Answer

$\frac{15}{x^3}$

Work Step by Step

$(5x^{-7})(3x^4)=(5)(3)(x^{(-7+4)})=15x^{-3}=\frac{15}{x^3}$
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