Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set - Page 742: 22

Answer

$\frac{5}{16}$

Work Step by Step

$4^{-1}+4^{-2}=\frac{1}{4}+\frac{1}{4^2}=\frac{1}{4}+\frac{1}{16}=\frac{1\times4}{4\times4}+\frac{1}{16}=\frac{4}{16}+\frac{1}{16}=\frac{5}{16}$
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