Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set: 29

Answer

$\frac{4}{9}$

Work Step by Step

$3^{-2}+3^{-1}=\frac{1}{3^2}+\frac{1}{3^1}=\frac{1}{9}+\frac{1\times3}{3\times3}=\frac{1}{9}+\frac{3}{9}=\frac{4}{9}$
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