Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Appendix B - Exercise Set: 32

Answer

$\frac{x^3}{27}$

Work Step by Step

$(\frac{3}{x})^{-3}=\frac{3^{-3}}{x^{-3}}=\frac{x^3}{3^3}=\frac{x^3}{27}$
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