Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 243: 60

Answer

∑(k=1, n)(16k^2 + 3)

Work Step by Step

2 * ∑(k=1, n)〖(3k^2 + 4) + 5〗* ∑(k=1, n)〖(2k^2 - 1)〗 = ∑(k=1, n)〖2(3k^2 + 4)〗+ ∑(k=1, n)〖5(2k^2 - 1)〗 = ∑(k=1, n)〖(6k^2 + 8)〗 + ∑(k=1, n)〖(10k^2 - 5)〗 = ∑(k=1, n)〖(6k^2 + 8) + (10k^2 - 5)〗 = ∑(k=1, n)(16k^2 + 3)
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