Answer
∑(k=1, n)(16k^2 + 3)
Work Step by Step
2 * ∑(k=1, n)〖(3k^2 + 4) + 5〗* ∑(k=1, n)〖(2k^2 - 1)〗
= ∑(k=1, n)〖2(3k^2 + 4)〗+ ∑(k=1, n)〖5(2k^2 - 1)〗
= ∑(k=1, n)〖(6k^2 + 8)〗 + ∑(k=1, n)〖(10k^2 - 5)〗
= ∑(k=1, n)〖(6k^2 + 8) + (10k^2 - 5)〗
= ∑(k=1, n)(16k^2 + 3)