Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 243: 33

Answer

$\frac{1}{1!}=1$

Work Step by Step

The summation of $\frac{1}{1^2}+\frac{1}{2^2}+\frac{1}{3^2}+......+\frac{1}{1^2};n=1$ will be $\frac{1}{1!}=1$
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