Answer
$\Sigma^n_{k=1}(k-5)$
Work Step by Step
$\Sigma^n_{k=1}[3(2k-3)+(4-5k)]$
=$\Sigma^n_{k=1}[(6k-9)+(4-5k)]$
--SIngle Summation will be
=$\Sigma^n_{k=1}(k-5)$
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 243: 59
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
