Answer
$11$
Work Step by Step
The lower limit of $k$ is $-1$ and the upper limit is $1$.
Thus, evaluate the given summation from $k=-1$ to $k=1$ to obtain:
$=[(-1)^2+3] + (0^2+3) + (1^2+3)
\\=(1+3)+(0+3) + (1+3)
\\=4+3+4
\\=11$
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