Answer
$\sum_{k=1}^{5}(-1)^{k-1}\frac{k+1}{(k+2)(k+3)}$
Work Step by Step
1. We can represent the alternating signs using $(-1)^{k-1}$
2. We can express the original summation as:
$\sum_{k=1}^{5}(-1)^{k-1}\frac{k+1}{(k+2)(k+3)}$
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 243: 46
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
