Answer
$\frac{22}{3}$
Work Step by Step
\begin{aligned} \int_{-3}^{-1} \frac{y^{5}-2 y}{y^{3}} d y&=\int _{-3}^{-1}\left(y^2-\frac{2}{y^2}\right)dy\\
&=\int _{-3}^{-1}\left(y^2-2y^{-2}\right)dy\\
&= \frac{1}{3}y^3+2y^{-1}\bigg|_{-3}^{-1}\\
&= \left(\frac{-1}{3}-2 \right) - \left(-9-\frac{2}{3}\right)\\
&=\frac{22}{3}\end{aligned}
