University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises: 10

Answer

$\pi$

Work Step by Step

$\int_{0}^{\pi} (1+cosx)dx=[x+sin x]_{0}^{\pi}=[\pi+sin \pi]-[0+sin0]= [\pi+0]-[0+0]=\pi$
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