Answer
$4$
Work Step by Step
$\int_{0}^{\pi/3} (4sec(u)tan(u)) du=4\cdot\int_{0}^{\pi/3} (sec(u)tan(u)) du=4\cdot[sec(u)]_{0}^{\pi/3}=4\cdot[sec(\frac{\pi}{3})]-4\cdot[sec(0)]=4\cdot2-4\cdot1=4$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 12
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