University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises: 12

Answer

$4$

Work Step by Step

$\int_{0}^{\pi/3} (4sec(u)tan(u)) du=4\cdot\int_{0}^{\pi/3} (sec(u)tan(u)) du=4\cdot[sec(u)]_{0}^{\pi/3}=4\cdot[sec(\frac{\pi}{3})]-4\cdot[sec(0)]=4\cdot2-4\cdot1=4$
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