Answer
$\frac{2\pi}{3}$
Work Step by Step
$\int_{0}^{1/2} (\frac{4}{\sqrt {1-x^2}}) dx=[4\cdot arcsin(x)]_{0}^{1/2}=[4\cdot arcsin(\frac{1}{2})]-[4\cdot arcsin(0)]=4\cdot\frac{\pi}{6}-4\cdot0=\frac{2\pi}{3}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises - Page 320: 31
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