University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises: 31

Answer

$\frac{2\pi}{3}$

Work Step by Step

$\int_{0}^{1/2} (\frac{4}{\sqrt {1-x^2}}) dx=[4\cdot arcsin(x)]_{0}^{1/2}=[4\cdot arcsin(\frac{1}{2})]-[4\cdot arcsin(0)]=4\cdot\frac{\pi}{6}-4\cdot0=\frac{2\pi}{3}$
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