University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.4 - The Fundamental Theorem of Calculus - Exercises: 6

Answer

26.25 or $\frac{105}{4}$

Work Step by Step

$\int_{-2}^3(x^3-2x+3) dx $ $((x^4/4)-x^2+3x)\Big|_1^4$ $((81/4)-9+9) -(4-4+-6)=26.25$
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