Answer
$\sum\limits_{k=1}^4k^2$
Work Step by Step
$1=1^2, 4=2^2, 9=3^2, 16=4^2$, therefore the additives are the first four square numbers, therefore the formula is: $\sum\limits_{k=1}^4k^2$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 5 - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises - Page 299: 12
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