#### Answer

$\sum\limits_{k=1}^5(-1)^{k}\cdot\frac{k}{5}$

#### Work Step by Step

The denominators of the fractions are fives, the sign is always changing, and the numerator always grows by one, therefore the formula is:
$\sum\limits_{k=1}^5(-1)^{k}\cdot\frac{k}{5}$