University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises - Page 299: 19

Answer

a) 55 b) 385 c) 3025

Work Step by Step

(a) Recall: \begin{equation}\sum_{k=1}^{n}k=\frac{n(n+1)}{2}\end{equation} \begin{equation}\implies\sum_{k=1}^{10}k=\frac{10(10+1)}{2}=55\end{equation} (b) Recall: \begin{equation}\sum_{k=1}^{n}k^{2}=\frac{n(n+1)(2n+1)}{6}\end{equation} \begin{equation}\implies\sum_{k=1}^{10}k^{2}=\frac{10(10+1)(2\times10+1)}{6}=385\end{equation} (c) Recall: \begin{equation}\sum_{k=1}^{n}k^{3}=\frac{n^{2}(n+1)^{2}}{4}\end{equation} \begin{equation}\implies\sum_{k=1}^{10}k^{3}=\frac{10^{2}\times(10+1)^{2}}{4}=3025\end{equation}
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