University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 5 - Section 5.2 - Sigma Notation and Limits of Finite Sums - Exercises - Page 299: 30

Answer

a) $630$ b) $1780$ c) $117648$

Work Step by Step

Use formula: $\Sigma_{k=1}^n k=\dfrac{n(n+1)}{2}$ and $\Sigma_{k=1}^n k^2=\dfrac{n(n+1)(n+2)}{6}$ a) Here, we have $\Sigma_{k=9}^{36} (k)=\Sigma_{j=1}^{28} (j+8)=\Sigma_{j=1}^{28} j+\Sigma_{j=1}^{28} 8=630$ b) Here, we have $\Sigma_{k=3}^{17} (k^2)=\Sigma_{j=1}^{15} (j+2)^2)=\Sigma_{j=1}^{15} j^2+4\Sigma_{j=1}^{15}j+\Sigma_{j=1}^{15} 4=1780$ c) Here, we have $\Sigma_{k=18}^{71} k(k-1)=\Sigma_{j=1}^{54} (j+17)(j+16)=\Sigma_{j=1}^{54} j^2+33 \Sigma_{j=1}^{54} j+\Sigma_{j=1}^{54} 272=117648$
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