Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 16 - Vector Calculus - 16.5 Exercises - Page 1122: 30

Answer

a) $\nabla \cdot r=3$ b) $\nabla \cdot (rr)=4r$ c) $\nabla^2 r^3=12r$

Work Step by Step

a) $\nabla \cdot r=(\dfrac{\partial }{\partial x}i+\dfrac{\partial }{\partial y}j+\dfrac{\partial}{\partial z}k) \cdot (x i+yj+zk)=1+1+1=3$ b) $\nabla \cdot (rr)=r \nabla \cdot r+r \cdot \nabla r$ $=(x i+yj+zk) \cdot (\dfrac{x}{r}i+\dfrac{y}{r}j+\dfrac{z}{r}k) =\dfrac{x^2+y^2+z^2}{r}=r$ Thus, $\nabla \cdot (rr)=3r+r=4r$ c) $\nabla r^3=\dfrac{\partial (r^3)}{\partial x}i+\dfrac{\partial(r^3) }{\partial y}j+\dfrac{\partial (r^3)}{\partial z}k=\dfrac{\partial (r^3)}{\partial r} \times (\dfrac{\partial r}{\partial x}i+\dfrac{\partial r}{\partial y}j+\dfrac{\partial r}{\partial z}k)=(3r^2) \nabla r $ Thus, $\nabla^2 r^3=3 \nabla \cdot (rr)=3(4r)=12r$
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