Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 16 - Vector Calculus - 16.5 Exercises - Page 1122: 29

Answer

$curl (curl F)=grad(div F) -\nabla^2 F$

Work Step by Step

We need to prove that $curl (curl F)=grad(div F) -\nabla^2 F$ This implies that $curl (curl F)=\nabla \times (\nabla \times F)$ or, $curl (curl F)=\nabla (\nabla \cdot F) -F (\nabla \cdot \nabla)$ or, $curl (curl F)=\nabla (div F) -F (\nabla^2)$ Hence, $curl (curl F)=grad(div F) -\nabla^2 F$
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