Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 12 - Vectors and the Geometry of Space - 12.6 Exercises - Page 857: 48

Answer

$\dfrac{x^2}{10000} +\dfrac{y^2}{10000}-\dfrac{z^2}{260416.67} =1$

Work Step by Step

The equation of a hyperboloid of one sheet with the z-axis and centered at the origin can be expressed as: $\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2}-\dfrac{z^2}{c^2} =1$ Set $y=0$ Now, $\dfrac{x^2}{a^2} -\dfrac{z^2}{c^2} =1$ Suppose $x=\dfrac{280}{2}; z=500$ So, $\dfrac{(140)^2}{(100)^2} -\dfrac{(500)^2}{c^2} =1 \implies -\dfrac{(500)^2}{c^2}=-0.96$ $\implies c^2=\dfrac{(500)^2}{0.96} \approx 260416.67$ The equation (1) becomes: $\dfrac{x^2}{10000} +\dfrac{y^2}{10000}-\dfrac{z^2}{260416.67} =1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.